Question

Calculati:
1.)√576-√625+√729-√841+√900=
b)√6400-√2025+√3364-√5184-√441=
c) (13√144-5*√196)*√√361-√225=
d) √3 la puterea 4 +3 la puterea 2 *2+1 *(2*√1296-3 * √841)=

Ps: * = inmultire
La c avem 2 radicali unul care sta in fata lui 361 si unul care tine amandoua numerele ...

Answer 1

√576=24.
√625=25.
√729=27.
√841=29.
√900=30.
√6400=80.
√2025=45.
√3364=58.
√5184=72.
√441=21.
√144=12.
√196=14.
√361=19.
√225=15.
√1296=36.


a) 24-25+27-29+30=-1-2+30=-3+30=27.

b) 80-45+58-72-21=35-14-21=21-21=0.

c) (13•12-5•14)•√19-15=(156-70)•√4=86•2=172.

d)(√3)^4+3^2•2+1(2•36-3•29)=3^2+9•2+(72-87)=9+18-15=9+3=12.

Sper ca te-am ajutat :)

Answer 2

1)√576-√625+√729-√841+√900=
=24-25+27-29+30=
=-1-2+30=27

 b)√6400-√2025+√3364-√5184-√441=
=80-45+58-72-21=
=35+58-93=
=93-93=0

c) (13√144-5×√196)×√(√361-√225)=
=(13×12-5×14)×√(19-15)=
=(156-70)×√4=
=86×2=172
 
d) √3⁴ +3² ×2+1×(2×√1296-3 × √841)=
= √3⁴ +18+1×(2×36-3 × 29)=
= 9 +18+72-87=12