Question

Calculati:
1 supra√2-3=


√6-4√3 supra 2√2-4=

Answer 1

$\frac{1}{ \sqrt{2}-3 } = \frac{ \sqrt{2}+3 }{2-9}= {(\sqrt{2} +3)}{/(-7})$

$\frac{ \sqrt{6}-4 \sqrt{3} }{2 \sqrt{2}-4 }= \frac{4 \sqrt{3}-8 \sqrt{6}+4 \sqrt{6}-16 \sqrt{3}}{4}= \frac{-12 \sqrt{3} -4 \sqrt{6} }{-8}={(3 \sqrt{3}+\sqrt{6)}}{/2}$

Answer 2

Am scris rezolvarea mai jos: