Question

Calculați 1) x la puterea a 2-a +x+2=0 si 2) -x la puterea a 2-a -x-1=0

Answer 1

1) x²+x+2=0
Δ=1-4×2=-7
x₁ =(-1-√-7)/2=(-1-i√7 )/2≈ -0,5000-1,3229i 
x₂ =(-1+√-7)/2=(-1+i√7 )/2≈ -0,5000+1,3229i

2) -x² -x-1=0
Δ=1-4=-3
 x₁ =(1-√-3)/(-2)=-1/2+i/2√ 3 ≈ -0,5000-0,8660i 
x₂ =(1+√-3)/(-2)=-1/2-i/2√ 3 ≈ -0,5000+0,8660i

Answer 2

1) x²+x+2=0 
Δ=1-4×2=-7
x₁ =(-1-√-7)/2=(-1-i√7 )/2≈ -0,5000-1,3229i  
x₂ =(-1+√-7)/2=(-1+i√7 )/2≈ -0,5000+1,3229i 

2) -x² -x-1=0 
Δ=1-4=-3
 x₁ =(1-√-3)/(-2)=-1/2+i/2√ 3 ≈ -0,5000-0,8660i  
x₂ =(1+√-3)/(-2)=-1/2-i/2√ 3 ≈ -0,5000+0,8660i  
Cam asa ceva