Question

calculati (10^2009-10^2008-10^2007):(9^2+2^3)

Answer 1

$(10^{2009}-10^{2008}-10^{2007}):(9^2+2^3)= \\ =10^{2007}(10^2-10-1):(9^2+2^3)= \\ =10^{2007} \cdot (100-10-1): (81+8)= \\ =10^{2007} \cdot 89:(81+8)=10^{2007} \cdot 89:89=10^{2007} \cdot 1=10^{2007}$

Answer 2

$( 10^{2009} - 10 ^{2008} -10^{2007} ):( 9^{2} + 2^{3} ) \\ ( 10 ^{2007} ( 10^{2} - 10^{1} -1)) : (89) \\ \frac{10 ^{2007}*89 }{89} = 10^{2007}$