Question

Calculati:10*{24^2:576+3*[(3^2*2)^15:(3^29*2^15)+1^21]}:13
2^100:[2^50*2^48+(2^10*2^15)^5:2^27+(5^76:5^75-3)90*2^8+2^98]

Answer 1

10*{24² : 576+3*[(3²*2)¹⁵:(3²⁹*2¹⁵)+1²¹]}:13=
=10*{24² : 24²+3*[(3³⁰*2¹⁵) :( 3²⁹*2¹⁵)+1]}:13=
=10*[1+3*(3+1)]:13=10*(1+3*4):13=10*13 : 13= 10

2^100:[2^50*2^48+(2^10*2^15)^5:2^27+(5^76:5^75-3)^90*2^8+2^98] =
=2¹⁰⁰ : [2⁹⁸+2¹²⁵: 2²⁷+(5-3)⁹⁰*2⁸+2⁹⁸]=2¹⁰⁰ : (2⁹⁸+2⁹⁸+2⁹⁰*2⁸+2⁹⁸)=
= 2¹⁰⁰ : (2⁹⁸+2⁹⁸+2⁹⁸+2⁹⁸)=2¹⁰⁰ : [ 2⁹⁸*(1+1+1+1)]= 2¹⁰⁰ : 2⁹⁸*2²= 2¹⁰⁰: 2¹⁰⁰=1