Question

calculati
16+4*{2+√2*[√2+3(√27-3√3)]-7la puterea 6}:(-1)la puterea 9=

Answer 1

$16+4*[2+ \sqrt{2} *[ \sqrt{2} +3( \sqrt{27} -3 \sqrt{3} )]-7 ^{6} ]:(-1) ^{9} =$
$16+4*[2+ \sqrt{2} *[ \sqrt{2} +3( 3\sqrt{3} -3 \sqrt{3} )]-7 ^{6} ]:(-1) =$
$16+4*[2+ \sqrt{2} *[ \sqrt{2} +3*0]-7 ^{6} ]:(-1) =$
$16+4*(2+ \sqrt{2} *\sqrt{2} -7 ^{6} ):(-1) =$
$16+4*(2+ 2 -7 ^{6} ):(-1) =16-4*(4 -7 ^{6} ) =$
$16-16 +7 ^{6} =7 ^{6}$