Question

Calculati:2^1×2^2×2^3....×2^20. b) [(3^2)^5÷3^7-3^0-3^2]×4÷34+2^2

Answer 1

a)2^1×2^2×2^3....×2^20=
=2^(1+2+3+..+20)=2^(20×21/2)=2^210


b) [(3^2)^5÷3^7-3^0-3^2]×4÷34+2^2 =
= [(3^10÷3^7-3^0-3^2]×2^2÷34+2^2 =
= [(3^3-3^0-3^2]×2^2÷34+2^2 =
= (27-1-9)×2^2÷34+2^2 =
= 17×2^2÷2×17+2^2 =
=2+2^2=
=2+4=6