Question

Calculati [2^2-(5^2-2^3×3)^47]^4:27.Multumesc anticipat!

Answer 1

=[4-(25-8*3]^47]^4:27=
[4-1^47]^4:27=
[4-1]^4:27=
3^4:27=84:27=3

Answer 2

$[ 2^{2} -( 5^{2} - 2^{3} *3) ^{47} ] ^{4} :27=$
$[4-(25-8*3) ^{47} ] ^{4} :27=$
[tex][4-(25-24) ^{47} ] ^{4} :27= [/tex]
[tex](4-1 ^{47} ) ^{4} :27= [/tex]
$3^{4} :27=81:27=3$