Question

Calculați: {2×3^3-3^2+3×[3+3×(3^3-3^5:3^3)]}:(2017^0+0^2017+2^1).
Multumesc

Answer 1

{2*27-9+3*[3+3*(27-3^2)]}:(1+0+2)=[2*27-9+3*(3+3*18)]:3=[2*27-9+3*(3+54)]:3

=(2*27-9+3*57):3=(54-9+171):3=(45+171):3=216:3=73