Question

calculati 2/3+3/4+5/6, 5/72+7/48, 2intregi 3/26+1 intreg 5/39, 6/5-1/4, 11/30- 5/90 , 2 intregi 1/5 -( 3/4+2/3) -13/30, 2intregi 1/22- 1intreg si 7/33 cine ma poate ajuta varog                                                      cine ma poate ajuta la ex asta

Answer 1

2/3+3/4+5/6=(2x4+3x3+5x2)/12=(8+9+10)/12=27/10=2,7

5/72+7/48=(5x2+7x3)/144=(10+21)/144=31/144
72=2³x3²
48=2⁴x3
[72,48]=2⁴x3²=16x9=144

2intregi3/26=(2x26+3)/26=55/26
1intreg 5/39=44/39
55/26+44/39=(55x3+44x2)/78=(165+88)/78=253/78
26=2x13
39=3x13
[26,39]=2x3x13=78

6/5-1/4=(6x4-1x5)/20=19/20

11/30-5/90=(11x3-5)/90=28/90=simplif=14/45

2intregi 1/5=11/5
11/5-(3/4+2/3)-13/30=
11/5-3/4-2/3-13/30=(11x12-3x15-2x20-13x2)/60=(132-45-40-26)/60=21/60=7/20
[5,4,3,30]=5x3x4=60

1intreg7/33=40/33
1/22-40/33=(3-40x2/66=-77/66=simplif=-7/6