Question

Calculati: [2,(3)x-1,(3)y] + [0,(6)x-0,(6)y] - (5x-4y)

Answer 1

[2,(3)x-1,(3)y] + [0,(6)x-0,(6)y] - (5x-4y)=[7/3x-4/3y] + [2/3x-2/3y] - (5x-4y)=7/3x-4/3y + 2/3x-2/3y - 15/3x+12/3y=x(7/3+2/3-15/3)-y(4/3+2/3-12/3)=x(-6/3)-y(-6/3)=-2x+2y=2y-2x

Answer 2

[tex][2,(3)x-1,(3)y] + [0,(6)x-0,(6)y] - (5x-4y)= \\ \\ ( 2\frac{3}{9}x+1 \frac{3}{9}y)+( \frac{6x}{9}- \frac{6y}{9})-5x+4y= \\ \\ \frac{21x}{9}+ \frac{12y}{9}+ \frac{6(x-y)}{9}-5x+4y= \\ \\ \frac{3(7x+4y)}{9}+ \frac{2(x-y)}{3} -5x+4y= \\ \\ \frac{7x+4y}{3}+ \frac{2x-2y}{3}-5x+4y= \\ \\ \frac{9x+2y}{3}- \frac{15x}{3}+ \frac{12y}{3}= \\ \\ \frac{14y-6x}{3}= \boxed{\frac{2(7y-3x)}{3}} [/tex]