Question

Calculați
(2^4)^4:2^2^4×(3^2-1)-2020^0×2^2.


​

Answer 1

 

$\displaystyle\bf\\\Big(2^4\Big)^4:2^{2^4}\times(3^2-1)-2020^0\times2^2=\\\\=2^{4\times4}:2^{\left(2^4\right)}\times(3^2-1)-2020^0\times2^2=\\\\=2^{16}:2^{16}\times(3^2-1)-2020^0\times2^2=\\\\=1\times(9-1)-1\times4=\\\\=1\times8-1\times4=\\\\=8-4=\boxed{\bf4}$