Question

calculati [(2^5)^2+2^5-7^0]÷[(2^2)^5+2^2×2^3-3^8÷3^8]

Answer 1

[(2^5)^2+2^5-7^0]:[(2^2)^5+2^2*2^3-3^8:3^8]=(2^10+2^5-1):(2^10+2^5-1)=1