Question

Calculati:
2^7:4^3+3^9•27^5:3^20+(3^1•2^4-4^2):2^3

Answer 1

2^7:4^3+3^9×27^5÷3^20+(3^1×2^4-4^2):2^3
128:64+3^9×(3^3)^5÷3^20+(3×16-16)÷2^3
2+3^9×3^15÷3^20+32÷2^3
2+3^24÷3^20+32÷2^3
2+3^4+32÷2^3
2+81+32÷8
83+4
87

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Answer 2

2^7 : 4^3 + 3^9 *27^5 : 3^20 + (3^1 * 2^4 -4^2) : 2^3 =
= 2^7 : (2^2)^3 + 3^9 * (3^3)^5 : 3^20 + [3 * 2^4 - (2^2)^2] : 2^3 =
= 2^7 : 2^6 + 3^9 * 3^15 : 3^20 + (3 * 2^4 - 2^4) : 2^3 =
= 2 ^(7-6) + 3^(9+15-20) + 2^4 * (3 - 1):2^3 =
= 2^1 + 3^4 + 2^4 * 2:2^3 = 
= 2 + 3^4 + 2^5:2^3 =
= 2 + 3^4 + 2^2 = 
= 2 * (1 + 2) + 3^4 =
= 2 * 3 + 3^4 = 
= 3 * (2 + 3^3) = 
= 3 * (2+27) = 
= 3 * 29 = 
= 87