Question

calculati:(2 la puterea 0+2 la puterea 1+2 la puterea 2) totul la puterea a 9:7 la puterea a 7+7 la puterea 2

Answer 1

(2^0+2^1+2^2)^9:7^7+7^2=
(1+2+4)^9:7^7+7^2=
7^9:7^7+7^2=
7^9-7+7^2=
7^2+7^2=49+49=98
sper că te-am ajutat

Answer 2

${( {2}^{0} + {2}^{1} + {2}^{2} ) }^{9} \div {7}^{7} + {7}^{2}$

$= {(1 + 2 + 4)}^{9} \div {7}^{7} + {7}^{2}$

$= {7}^{9} \div {7}^{7} + {7}^{2}$

$= {7}^{9 - 7} + {7}^{2}$

$= {7}^{2} + {7}^{2}$

$= 49 + 49$

$=9 8$