Question

calculati :2 la puterea 3+2 la puterea 10:2 la puterea 8×2+2×2 la puterea 7:2 la puterea 5+2 la puterea 10 :(3×2 la puterea 5+2 la puterea 5)-4×2 la puterea 3

Answer 1

[tex]2^2+2^1^0:2^8*2+2*2^7:2^5+2^1^0:(3*2^5+2^5)-4*2^3=\\ 8+2^2+2*2^2+2^1^0:(3*32+32)-4*8=\\ 8*4*2+2*4+2^1^0:(96+32)-32=\\ 8+8+8+261^0:128-32=\\ 24+(2^2)^5:128-32=\\ 24+4^5:128-32=\\ 24+1024:128-32=\\ 24+8-32=\\ 32-32=0[/tex]