Question

calculati:[(2 la puterea 7)la 5:2 la puterea 14×(2 la puterea 6+2 la puterea 6)-4 la puterea 6:2 la puterea 10]:(2 la puterea 28 -2 la puterea 2)+9

Answer 1

[(2^7)^5:2^14x(2^6+2^2)-4^6:2^10]:(2^28-2^2)+9=
[2^35:2^14x(2x2^6)-(2^2)^6:2^10]:(2^28-2^2)+9=
(2^35:2^14x2^7-2^12:2^10):(2^28-2^2)+9=
(2^28-2^2):(2^28-2^2) +9 =
1+9=
10