Question

Calculati 2 la puterea a șaptea : la 4 la a treia + 3 la a noua × 27 la a cincea : 3 la 20 + ( 3 la puterea a întâia ×2 la a patra -4 la a doua ) ÷ la 2 la a treia

Answer 1

Rezolvare

2^7:4^3+3^9×27^5:3^20+(3^1×2^4-4^2):2^3=

2^7:(2^2)^3+3^9×(3^3)^5:3^20+(3×16-16):8=

2^7:2^6+3^9×3^15:3 ^20+(48 - 16):8 =

2^(7-6)+3^(9+15):3^20 +32 :8 =

2^1+3 ^24 :3^20 +4 =

2 +3^(24-20) +4 =

2 +3 ^4 +4 =

2 +81 +4 =

83 +4 =

87

Răspuns :87

Answer 2

Răspuns: 87

$\it 2^{7}:4^{3}+3^{9}\cdot27^{5}:3^{20}+(3^{1}\cdot2^{4}-4^{2}):2^{3}=\\\\ 2^{7} : (2^{2})^{3} +3^{9}\cdot(3^{3})^{5}:3^{20} +(3\cdot16-16):8 =\\\\ 2^{7} : 2^{3\cdot3} +3^{9}\cdot3^{15}:3^{20} +32:8 =\\\\2^{7} : 2^{6} +3^{9+15-20} +4 = \\\\2^{7-6} +3^{4} +4 = \\\\2^{1} +3^{4} +4 =\\\\2+81+4=\\\\\boxed{\it 87}$