Question

calculati (2-rad din 2)^2+2 rad din 2 (2-2rad din 2) + 2

Answer 1

$(2- \sqrt{2} )^2+2 \sqrt{2} (2-2 \sqrt{2} )+2= \\ =2^2-2 \cdot 2 \cdot \sqrt{2}+ \sqrt{2} ^2+ 4 \sqrt{2} -8+2= \\ =4-4 \sqrt{2} +2+4 \sqrt{2} -8+2=0$