Question

calculati (2 radical3-3)(radical3+1)

Answer 1

(2√3-3)(√3+1)=2*3-3√3+2√3-3=6-√3-3=3-√3

Answer 2

$(2 \sqrt{3} - 3)( \sqrt{3} + 1) = \\ \\ 6 + 2 \sqrt{3} - 3 \sqrt{3} - 3 = \\ \\ (6 - 3) + (2 \sqrt{3} - 3 \sqrt{3}) = \\ \\ 3 - \sqrt{3}$