Question

calculati 24supra 5√3-12suprA √9plus 21supra10√6-28supra 2√6

Answer 1

Explicație pas cu pas:

$\dfrac{24}{5 \sqrt{3} } - \dfrac{12}{ \sqrt{9} } + \dfrac{21}{10 \sqrt{6} } - \dfrac{28}{2 \sqrt{6} } =$

$\dfrac{24 \sqrt{3} }{5 \cdot3 } - \dfrac{12}{ 3 } + \dfrac{21 \sqrt{6} }{10 \cdot6} - \dfrac{28 \sqrt{6} }{2 \cdot6} =$

$\dfrac{ ^{12)}8 \sqrt{3} \: }{5 } - \dfrac{^{60)}4 \: }{ 1 } + \dfrac{^{3)}7 \sqrt{6} }{20} - \dfrac{^{20)}7\sqrt{6} \: }{3} =$

$\dfrac{ 96\sqrt{3} }{60}- \dfrac{240 }{60 }+ \dfrac{21 \sqrt{6} }{60} - \dfrac{140\sqrt{6}}{60} =$

$\dfrac{ 96 \sqrt{3} - 240 + 21 \sqrt{6} - 140\sqrt{6}}{60} =$

$\red{\boxed{\dfrac{ 96\sqrt{3} - 240 - 119\sqrt{6}}{60}}}$