Question

calculati:
252:6+(435:5+14+129x3=

1+(705:5+381:3x2):5-576:9=
 
1000-(432:4+278x2):4x5+714:7-a=612:9

(3x239-48x6+831:3-742:7):3:a=4

va rog mult!!!

Answer 1

252:6+(435:5+14)+129x3 = 42+(87+14)+387 = 42+101+387 = 530 ;
(Obs. acesta , daca paranteza rotunda se inchide dupa 14 !)

1+(705:5+381:3x2):5-576:9 = 1+(141+254):5-64 = 1+79-64 = 16 ;

1000-(432:4+278x2):4x5+714:7-a=612:9
1000-(108+556):4*5+102 - a =68
1000-830+102 - a = 68
a = 272-68
a = 204 ;

(3x239-48x6+831:3-742:7):3:a=4
(717-288+277-106):3:a=4
600:3:a=4
200:a=4
a=200:4
a=50 ;