Question

Calculati (28,42,63) si [28,42,63]

Determiati numerele prime a si b stiind ca 3a+12b=66
Va rog ajutati-ma!

Answer 1

$28= 2^{2} *7 \\ 42=2*3*7 \\ 63= 3^{2} *7 \\ \\ cmmdc=2*3*7=42 \\ cmmmc= 2^{2} * 3^{2} *7=252 \\ \\ 3a+12b=66 \\ 3(a+4b)=66 \\ a+4b=22 \\ \\ a+4b=2+4*5 \\ a=2 \\ 4b=4*5 \\ b=5$