Question

Calculați: 29 ) lim x->-infinit 3,8 la puterea 7-x.Va rog

Answer 1

 

$\displaystyle\bf\\\lim_{x\to-\infty}3,\!8^{7-x}=\lim_{x\to\infty}3,\!8^{7+x}=3,\!8^{7+\infty}=3,\!8^{\infty}=\boxed{\bf\infty}\\\\\\\implies\boxed{\bf\lim_{x\to-\infty}3,\!8^{7-x}=\infty}$