Question

Calculati:
(2a+1)^2-4a(a+1)
Daca x^2+1pe x^2=2,calculati x+1pe x
Dau coroană

Answer 1

(2a+1)^2-4a(a+1)=4a^2+4a+1-4a^2-4a=1

x^2+1pe x^2=2⇔x^2+1=2x^2⇔2x^2-x^2=1⇔x^2=1⇔x=1 sau s=-1

daca x=1 x+1pe x=(1+1)/1=2/1=2
daca x=-1 x+1pe x=(-1+1)/-1=0