Question

Calculati 2a+3b+c,stiind ca:
a=(5+5:5+2-2:2)×2
b=[36-16:(25:5-12:3)]:5-4
c=7+3×[2-27:(5×5+2:1)]
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Answer 1

a=(5+5:5+2-2:2)*2

a=(5+1+2-1)*2

a=7*2

a=14

b=[36-16:(25:5-12:3)]:5-4

b=[36-16:(5-4)]:5-4

b=(36-16:1):5-4

b=(36-16):5-4

b=20:5-4

b=4-4

b=0

c=7+3[2-27:(5*5+2:1)]

c=7+3(2-27:27)

c=7+3(2-1)

c=7+3

c=10

3b+c=2*14+3*0+10=28+0+10=38