Question

calculați:2la puterea 7 :4la puterea 3 +3^9 ×27^5:3^20+(3^1×2^1-4^2):2 vă rogggggg dau coroanaaaaaaaaa plssssssssssssssssssssss​

Answer 1

Răspuns:

Explicație pas cu pas:

2^7:4^3+3^9×27^5:3^20+(3^1×2^1+4^2):2 =

2^7:(2^2)^3 +3^9×(3^3)^5 :3^20 + (3×2+16):2 =

2^7:2^6 +3^9×3^15:3^20 +(6+16):2 =

2 ^(7-6)+3^(9+15):3^20 +22:2 =

2 +3^24:3^20 +11 =

2 + 3^(24-20)+11 =

2 + 3^4+11 =

2+81+11 =

83+11 =

94

PS : Am scris " +4^2 "