Question

Calculati 2x+4y-3z, unde:
X=[6,4]+[5/2]-[2,(3)]+[-4/3]+[-3,01]
Y={1,4}+{-1,5}-{3/4}+{-1,(3)}-{2/3}
Z=[2,71]+{3,9}-[-0,2]+{6}+[-3]+{21/10}
va rooog

Answer 1

X=[6,4]+[5/2]-[2,(3)]+[-4/3]+[-3,01]=
=6,4+5/2-(23-2)/9-4/3-3,01=
=3,39+5/2-7/3-4/3=
=3,39+(15-14-8)/6=
=339/100-7/6=
=(1017-350)/300=
=667/300=2,22(3)


 Y={1,4}+{-1,5}-{3/4}+{-1,(3)}-{2/3}=
=1,4-1,5-3/4-(13-1)/9-2/3=
=-0,1-3/4-12/9-2/3=
=-0,1-3/4-4/3-2/3=
=-0,1-3/4-6/3=
=-2,1-3/4=
=-21/10-3/4=
=(-42-15)/20=
=-57/20=-2,85

 Z=[2,71]+{3,9}-[-0,2]+{6}+[-3]+{21/10}=
=2,71+3,9+0,2+6-3+21/10=
=9,81+21/10=
=981/100+21/10=
=(981+210)/100=
=1191/100=11,91

2x+4y-3z=2*2,22(3)+4*(-2,85) -3*11,91=4,44(6)-11,4-35,73=-42,68(3)