Question

Calculati:3+1/2;4/3+0;1/7+(-4/3)+6/7+1/3;100/200+101/303+50/300;3 intregi 3/4(-3intregi 1/4)

Answer 1

$^{2)}3+\frac{1}{2} =\frac{6+1}{2}=\frac{7}{2}=3\frac{1}{2}$

4/3+0 = 4/3 = 1 si 1/3

$\frac{1}{7}+ \frac{-4}{3}+\frac{6}{7}+\frac{1}{3} =\frac{1}{7}+\frac{6}{7}-\frac{4}{3}+\frac{1}{3}=\frac{7}{7}-\frac{3}{3}=1-1=0$

100/200+101/303+50/300=

(100/200) + (101/303) + 50/300 = (1/2) + (1/3) + 1/6= ( numitor comun 6)

=(3 + 2 + 1)/6 = 6/6 = 1

$3\frac{3}{4} -3\frac{1}{4}=\frac{3\cdot4+3}{4}-\frac{3\cxdot4+1}{4}=\frac{15-13}{4}=\frac{2}{4}=\frac{1}{2}$