Question

Calculați : 3+3x[3+3x(3+3x3)]=(3xa+3)X3+3=
Repede va rog ,dau coroana !!!!! Va rog!!!

Answer 1

Răspuns:

a = 12

Explicație pas cu pas:

3+3x[3+3x(3+3x3)]=(3xa+3)X3+3

3+3x[3+3x(3+9)]=(3xa+3)X3+3

3+3x[3+3x12]=(3xa+3)X3+3

3+3x[3+36]=(3xa+3)X3+3

3+3x39=(3xa+3)X3+3

3+117=(3xa+3)X3+3

120=(3xa+3)X3+3

(3xa+3)X3= 120 -3

(3xa+3)X3= 117

3xa + 3 = 117 : 3

3 x a + 3 = 39

3 x a = 39 - 3

3 x a = 36

a = 36 : 3

a = 12