Question

Calculati:
√3(4+√6)-(√12-√18)+(√27+2√6):√3-(√8+3)

Answer 1

4√3+3√2-2√3+3√2+3+2√2-2√2-3=

(4√3-2√3)+(3√2+3√2+2√2-2√2)+3-3=2√3+6√2

Answer 2

Explicație pas cu pas:

Calculam primele 2 paranteze:

4r3+r18-r12+r18=4r3+2r18-r12=4r3+2r9*r2-r4*r3=

4r3+2*3r2-2r3=4r3+6r2-2r3=2r3+6r2

Calculam a 3 a paranteza :

(r27+2r6)/r3=(r9*r3+2r2*r3)/r3=(3r3+2r2*r3)/r3=

r3(3+2r2)/r3=3+2r2

Avem:

2r3+6r2+3+2r2-r8-3=2r3+8r2-r4*r2=2r3+8r2-2r2=

2r3+6r2