Question

Calculați
3 supra 5 ori 10 supra 27
4 supra 7 ori 49 supra 48
8 supra 9 ori 27 supra 128
5 supra 6 ori 18 supra 25 ori 35 supra 36
3 supra 4 (1 supra 2 + 2 supra 3+ 5 supra 6)

Answer 1

1)SE SIMPLIFICA 10 CU 2 SI 27 CU 3 =2*3=6

2)SE SIMPLIFICA=7*12=84

3)3*16=48

4)SIMPLIFICI PRIMELE DOUA FRACTII =3/5*35/36=7*21=147

5)ADUCI PARENTEZA LA ACELASI NUMITOR ADICA 6=3*2=6

Answer 2

( 3 / 5 ) x ( 10 / 27 ) = ( 3 / 27 ) x ( 10 / 5 ) = ( 1 / 7 ) x 2 = 2 / 7

( 4 / 7 ) x ( 49 / 48 ) = ( 49 / 7 ) x ( 4 / 48 ) = 7 x ( 1 / 12 ) = 7 / 12

( 8 / 9 ) x ( 27 / 128 ) = ( 8 / 128 ) x ( 27 / 9 ) = ( 1 / 16 ) x 3 = 3 / 16

( 5 / 6 ) x ( 18 / 25 ) x ( 35 / 36 ) = ( 5 x 35 ) / 25   x   18 / ( 6 x 36 ) = 7 x ( 1 / 12 ) = 7 / 12

( 3 / 4 ) x ( 1 / 2 + 2 / 3 + 5 / 6 ) =

= 3 / 4  x ( 3 + 4 + 5  ) / 6 =

=  ( 3 / 4 )  x ( 12 / 6 ) =

=   ( 3 x 2 ) / 4 =

= 3 / 2 = 1 intreg si 1 / 2 = 1,5