Question

calculati
a/(7supra6+0,75):23supra5+0,58(3)

b/ [5supra6-0,(6)]:0,1(6)

c/ [0,3(6)-0,125]:29supra40-0,(3)

d/ [0,91(6)-0,(7)]:23supra12+0,(6)

Answer 1

(7supra6+0,75):23supra5+0,58(3) =
=(7/6 +3/4)x5/23 +(583-58)/900=
=[(14+9)/12]x5/23 +525/900=
=(23/12)x5/23 +7/12=5/12+7/12=12/12=1

 [5supra6-0,(6)]:0,1(6)=(5/6 -6/9):[(16-1)/90]=
=[(15-12)/18]:15/90=(3/18):(1/6)=(1/6)x6=1

[0,3(6)-0,125]:29supra40-0,(3)=[(36-3)/90 -1/8]x40/29 -1/3=
(33/90 -1/8)x40/29 -1/3=(11/30 -1/8)x40/29 -1/3=
=(44/120 -15/120)x40/29 -1/3=(29/120)x40/29 -1/3=
=40/120 -1/3=1/3 -1/3=0

[0,91(6)-0,(7)]:23supra12+0,(6)=[(916-91)/900 -7/9]x12/23 +2/3=
(825/900 -7/9)x12/23 +2/3=(11/12 -7/9)x12/23 +2/3=
(33/36 -28/36)x12/23 +2/3=(5/36)x12/23 +2/3=5/(3x23) +2/3=
=(5+46)/(3x23)=51/(3x23)=(17x3)/(3x23)=17/23