Question

Calculați:3radical din 24-radical din 54-2 radical din 96 +radical dun 150= vă rog frumos ​

Answer 1

Răspuns:

Explicație pas cu pas:

$3\sqrt{24} - \sqrt{54} -2\sqrt{96} +\sqrt{150} =$

$=3\sqrt{4*6} - \sqrt{9*6} -2\sqrt{16*6} +\sqrt{25*6} =$

$=3\sqrt{4}*\sqrt{6} - \sqrt{9}*\sqrt{6} -2\sqrt{16}*\sqrt{6} +\sqrt{25}*\sqrt{6} =$

$=3*2*\sqrt{6} - 3*\sqrt{6} -2*4*\sqrt{6} +5*\sqrt{6} =$

$=6*\sqrt{6} - 3*\sqrt{6} -8*\sqrt{6} +5*\sqrt{6} =$

$=\sqrt{6}*(6 - 3 -8 +5) = =\sqrt{6}*0 = 0$

Answer 2

Răspuns: $\bf \red{\underline{~0~}}$

Explicație pas cu pas:

$\bf 3\sqrt{24} - \sqrt{54} -2\sqrt{96} +\sqrt{150} =$

$\bf 3\sqrt{2^{2} \cdot6} - \sqrt{3^{2} \cdot6} -2\sqrt{4^{2} \cdot6} +\sqrt{5^{2} \cdot6} =$    

$\bf 3\cdot2\cdot\sqrt{6} - 3\cdot\sqrt{6} -2\cdot4\cdot\sqrt{6} +5\cdot\sqrt{6} =$

$\bf \blue{\underline{6\sqrt{6}}}- 3\sqrt{6} -8\sqrt{6} +\blue{\underline{5\sqrt{6}}} =$

$\bf 11\sqrt{6} - 11\sqrt{6} = \red{\underline{~0~}}$