Question

calculati : 4^23×2^10÷8^2 =

Answer 1

${4}^{23} \times {2}^{10} \div {8}^{2} = {( {2}^{2} )}^{23} \times {2}^{10} \div {( {2}^{3} )}^{2}$

$= {2}^{2 \times 23} \times {2}^{10} \div {2}^{3 \times 2}$

$= {2}^{46} \times {2}^{10} \div {2}^{6}$

$= {2}^{46 + 10 - 6}$

$= {2}^{50}$