Question

Calculați:
[(4√6)/3 + (√2+√6)/4] totul supra√2/2
Vă rog mult dau coroniță!

Answer 1

$\frac{ \frac{4 \sqrt{6} }{3}+ \frac{ \sqrt{2}+ \sqrt{6} }{4} }{ \frac{ \sqrt{2} }{2} } = \frac{16 \sqrt{6}+3 \sqrt{2}+3 \sqrt{6} }{12} * \sqrt{2}$
$( \frac{19 \sqrt{6}+3 \sqrt{2})* \sqrt{2} }{12} = \frac{19 \sqrt{12}+6 }{12} = \frac{38 \sqrt{3}+6 }{12} = \frac{2(19 \sqrt{3}+3) }{12} = \frac{19 \sqrt{3}+3 }{6}$