Question

calculati : 4 la -2 * 16 la a 2/2la a 3

Answer 1

   
[tex]\displaystyle \\ \frac{4^{-2} \times 16^2}{2^3} = \frac{16^2}{4^{2} \times 2^3} = \frac{(2^4)^2}{(2^2)^{2} \times 2^3} = \\ \\ = \frac{2^{4\times 2}}{2^{2\times 2} \times 2^3} = \frac{2^{8}}{2^{4} \times 2^3} = 2^{8-4-3} = 2^{8-7} = 2^1 = \boxed{2} [/tex]