Question

calculati (4/radical 12 - 6/radical 27+8/radical 32):radical 2.

Answer 1

[tex]8 \sqrt{3} - 12\sqrt{3} + 32\sqrt{2} : \sqrt{2} = - 4\sqrt{3} + 32[/tex]

Answer 2

(4/√12-6/√27+8/√32):√2=
4/2√2-6/3√3+8/4√2):√2=
(2/√2-2/√3+2/√2):√2=
(4/√2-2√3):√2=
(12/√6-4/√6):√2=
8/√6*1/√2=8/√12=8/2√3=4/√3=4√3/3