Question

Calculati:
4(x+1) + 3(x+2y)=?
5a-3(a-2) - 5(-2a+1)=?
5ab - 4b(2a-5) - 3a(3b+4)=?
(x+3)(x+2) + (x+3)(x+1)=?
VĂ ROG DACĂ NU ŞTIŢI NU SCRIEŢI.
TREBUIE SĂ FIE CORECTE TOATE.

Answer 1

1) 4(x+1)+3(x+2y)=(4)(x)+(4)(1)+(3)(x)+(3)(2y)=4x+4+3x+6y=(4x+3x)+(6y)+(4)=7x+6y+4y

2) 5a−3(a−2)−5(−2a+1)=5a+(−3)(a)+(−3)(−2)+(−5)(−2a)+(−5)(1)=5a+−3a+6+10a+−5=(5a+−3a+10a)+(6+−5)=12a+1

3) 5ab−4b(2a−5)−3a(3b+4)=5ab+−8ab+20b+−9ab+−12a=(5ab+−8ab+−9ab)+(−12a)+(20b)=−12ab+−12a+20b

4) (x+3)(x+2)+(x+3)(x+1)=(x)(x)+(x)(2)+(3)(x)+(3)(2)+(x)(x)+(x)(1)+(3)(x)+(3)(1)=x2+2x+3x+6+x2+x+3x+3=(x2+x2)+(2x+3x+x+3x)+(6+3)=2x2+9x+9