Question

calculati 5/8+0,8 (3)×[(2-1/3)×6-12/5:0,3] ȘI [(2/3-5/12)×24-0,45]:(7,25-3,92)

Answer 1

5/8+0,8 (3)×[(2-1/3)×6-12/5:0,3] =
=5/8 + 83-8totul supra/90 ×[(2/1-1/3)×6/1 -12/5 : 3/10]=
=5/8 + 75/90 ×(3×2-1 totul supra /3 × 6/1 - 12/5×10/3)=
=5/8 + 75/90 ×(5/3 ×6/1 - 4×2 totul supra/1×1)= (deci este supra 1×1 ☺)
=5/8 +75/90 ×(5×2 totul supra /1×1 -8/1 )=
=5/8 +75/90 ×(10/1 -8/1)=
=5/8 +75/90 × 2/1 =
=5/8 + 75×1 totul supra /45×1 =
=5/8 +75/45 =
=45×5+8×75 totul supra /360=
=225+600 totul supra /360=
=825/600 (simplificat cu 25)=
=33/24 (simplificat cu 3)=
=11/8









[(2/3-5/12)×24-0,45]:(7,25-3,92)=
=(4×2-5 totul supra /12 ×24/1 -45/100) :(725/100 -392/100)=
=(8-5 totul supra /12 ×24/1 - 45/100): 333/100=
=(3/12 ×24/1 -45/100): 333/100=
=( 3×2 totul supra /1×1 -45/100): 333/100=
=(6/1 -45/100): 333/100=
=100×6-45 totul supra /100 : 333/100=
=600-45 totul supra /100 : 333/100=
=555/100 :333/100=
=555/100 × 100/333=
=5×1 totul supra /1×3=
=5/3