Calculati (5 intregi si 3 /5 -1 intregi si 1/3) :( 7 intregi 7 /12 -2 intregi si 1/4 )= ....VA ROG
Răspunsuri la întrebare
Răspuns de
6
28/5-4/3=84/15-20/15=64/15
91/12+9/4=91/12+27/12=118
91/12+9/4=91/12+27/12=118
Răspuns de
5
Mai intai introduci intregii in fractie.
5 3/5=(5x5+3)/5=28/5
1 1/3=(1x3+1)/3=4/3
7 7/12=(7x12+7)/12=91/12
2 1/4=(2x4+1)/4=9/4
Transcriem exercitiul:
(28/5+4/3):(91/12-9/4), aducem la acelasi numitor fiecare paranteza
[(28x3+4x5)/15]:[(91+9x3)]/12
[(84+20)]/15]:[(91+27)]/12
(104/15):(118/12)
(104/15)x(12/118), simplificam cu 3 si 4
104/5x1/27=104/135
5 3/5=(5x5+3)/5=28/5
1 1/3=(1x3+1)/3=4/3
7 7/12=(7x12+7)/12=91/12
2 1/4=(2x4+1)/4=9/4
Transcriem exercitiul:
(28/5+4/3):(91/12-9/4), aducem la acelasi numitor fiecare paranteza
[(28x3+4x5)/15]:[(91+9x3)]/12
[(84+20)]/15]:[(91+27)]/12
(104/15):(118/12)
(104/15)x(12/118), simplificam cu 3 si 4
104/5x1/27=104/135
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