Question

Calculați [5 la puterea 5 ×5 la puterea 20) :5 la puterea 22-5 la puterea 22 -5 la puterea 2:5]:2 la puterea 3 b) [2 la puterea 3+ (2 la puterea 7× la puterea 0 ​factorul comun

Answer 1

$a) [(5^5*5^{20}):5^{22}-5^{22}-5^2-5]:2^3=\\ (5^{25}:5^{22}-5^{22}-5^2-5):8=\\(5^3-5^{22}-5^2-5):8=\\5(5^2-5^{21}-5-1):8=\\5(19-5^{21}):8=\\b)[2^3+(2^7*2^0)]=\\2^3+2^7=2^3(1+2^4)=\\8*16=128$