Question

Calculati. 64 la a 2 inmultit 2 la minus 2 tot la puterea a 3 totul supra 27​

Answer 1

$\displaystyle{ \frac{(64^{2}\cdot 2^{-2})^{3}}{27} = }$

$\displaystyle{ = \frac{[(2^{6})^{2} \cdot \frac{1}{2^{2}}]^{3}}{27} }$

$\displaystyle{ =\frac{(\frac{2^{12}}{2^{2}})^{3}}{27} }$

$\displaystyle{ =\frac{(2^{10})^{3}}{3^{3}} }$

$\displaystyle{ =\frac{2^{30}}{3^{3}} }$