Question

Calculați. Varog urgent! ​

Answer 1

a)

$\it \dfrac{1}{6}+\dfrac{^{2)}1}{\ 3}= \dfrac{1}{6}+\dfrac{2}{6}=\dfrac{1+2}{6}=\dfrac{\ 3^{(3}}{6}=\dfrac{1}{2}$

Acum, a)  devine:

$\it \Big(\dfrac{1}{2}-\dfrac{1}{2}\Big)^{100}=0^{100}=0$

d)

$\it 2\dfrac{1}{2}=\dfrac{5}{2}$

Acum se poate scrie:

$\it \Big(\dfrac{5}{2}\Big)^{15}:\Big(\dfrac{5}{2}\Big)^{10}:\Big(\dfrac{5}{2}\Big)^{4}=\Big(\dfrac{5}{2}\Big)^{5}:\Big(\dfrac{5}{2}\Big)^{4}=\dfrac{5}{2}$

Answer 2

Răspuns:

Explicație pas cu pas: