Question

calculati: (7^2-3^2)÷2^3+[(3+2×3)^2-15^0]÷(2^2×5)

Answer 1

(49-9)/8+[(3+6)^2-1]/(4*5)=40/8 +81-1/20=5+80/20=5+4=9

Answer 2

   (7^2-3^2)÷2^3+[(3+2×3)^2-15^0]÷(2^2×5) = 
= (49-9):8 + [(3+6)^2-1] : (4x5) =
= 40:8 + (9^2-1) : 20 = 
= 5 + (81-1):20 = 
= 5 + 80:20 =
= 5 + 4 = 
= 9