Question

Calculati:


(7⁶)⁸÷49²⁴
(3⁴)⁹÷(9⁶)³
(11²⁰¹¹ ×4¹⁰⁰⁵)÷[(22²)⁵]²⁰¹
2²³÷2²¹÷2+3³²÷3³¹×



E urgentt =/
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Answer 1

$7^{6*8}:7(^{2})^{24} =7^{48}:7^{48} =7^{48-48} =7^0=1\\3^{4*9}:(3^{2*6})^3=3^{36}:3^{12*3}=3^{36}:3^{36}=3^{36-36}=3^{0}=1\\(11^{2011})*(2^2)^{1005}:(22)^{2*5*201}=(11*11^{2010}*2^{2010}):22^{2010}\\11*22^{2010}:22^{2010}=11*22^{2010-2010}=11*22^{0}=11*1=11\\2^{(23-21-1)}+3^{(32-31)}=2^{1}+3^{1}=2+3=5$