Question

calculati [8×23] la puterea 3-2 la puterea6×46 la puterea3+2009 la putrea 0

Answer 1

Răspuns:

1

Explicație pas cu pas:

$(8 \times 23) ^{3} - 2 ^{6} \times 46 {}^{3} + 2009 {}^{0} = \\ 6229504 - 64 \times 97336 + 1 = \\ 6229504 - 6229504 + 1 = \\ 0 + 1 = 1$

Answer 2

$\it (8\cdot23)^3 -2^6\cdot46^3+2009^0=(2^2\cdot2\cdot23)^3 -2^6\cdot46^3+1=\\ \\ =2^6\cdot46^3-2^6\cdot46^3+1=1$