Question

Calculați. (8×9-4÷2)-(91-9×9)=?,,, (4×8+3×9+21)÷10÷(40-9×4)=?,,,,56÷(100-8×5-6×5-7×3-1)=?,,,,100-(27+7×6-48÷8)÷7=?,,,12+6÷(3+9÷3)=?,,,21-21÷7×(4-5÷5)=?,,,50÷10÷5+90÷9=???,,,Va rog,ajutați ma.Multumesc!!

Answer 1

(8x9-4:2)-(91-9x9)=
(72-2)-(91-81)=
70-10=60

(4x8+3x9+21):10:(40-9x4)=
(32+27+21):10:(40-36)=
80:10:4=
8:4=2

56:(100-8x5-6x5-7x3-1)=
56:(100-40-30-21-1)=
56:(60-30-21-1)=
56:(30-21-1)=
56:8=7

100-(27+7x6-48:8):7=
100-(27+42-6):7=
100-(69-6):7=
100-63:7=
100-9=91

12+6:(3+9:3)=
12+6:(3+3)=
12+6:6=
12+1=13

21-21:7x(4-5:5)=
21-3x(4-1)=
21-3x3=
21-9=12

50:10:5+90:9=
5:5+10=
1+10=11

Mult succes la școală!

Answer 2

(8×9-4÷2)-(91-9×9) = ( 72 - 2 ) - ( 91 - 81 ) = 70 - 10 = 60
(4×8+3×9+21)÷10÷(40-9×4) = ( 32 + 27 + 21 ) : 10 : ( 40 - 36 ) = 80 : 10 : 16 = 8 : 16 = 0,5 sau 1/2
56÷(100-8×5-6×5-7×3-1) = 56 : ( 100 - 40 - 30 - 21 - 1 ) = 56 : 8 = 7
100-(27+7×6-48÷8)÷7 = 100 - ( 27 + 42 - 6 ) : 7 = 100 - 63 : 7 = 100 - 9 = 91
12+6÷(3+9÷3) = 12 + 6 : 15 = 12 + 6 pe 15 = 12 întregi şi 2 treimi 
21-21÷7×(4-5÷5) = 21 - 3 x ( 4 - 1 ) = 21 - 3 x 3 = 21 - 9 = 12
50÷10÷5+90÷9 = 5 : 5 + 10 = 1 + 10 = 11
Sper că te-am ajutat :*