Question

calculati 8 la puterea 16:(2*2 la puterea 2*4 la puterea 10) totul la puterea 2 -2 la puterea1 -2 la puterea 0

Answer 1

$8^{16}:(2*2^2*4^{10})^2-2^1-2^0=(2^3)^{16}:(2*2^2*(2^2)^{10})^2-2-1=\\=2^{48}:(2^{23})^2-3=2^{48}:2^{46}-3=2^2-3=4-3=1$