Question

Calculati 9 la puterea -1 supra lui 3 la puterea -3 - radical din 18 supra lui radical din 2

Answer 1

$\frac{ {9}^{ - 1} }{ {3}^{ - 3} } - \frac{ \sqrt{18} }{ \sqrt{2} }$

$= \frac{ \frac{1}{9} }{ \frac{1}{ {3}^{3} } } - \frac{3 \sqrt{2} }{ \sqrt{2} }$

$= \frac{1}{9} \times {3}^{3} - 3$

$= \frac{1}{9} \times 27 - 3$

$= \frac{27}{9} - 3$

$= 3 - 3$

$= 0$

Answer 2

9^(-1)= 1/9
3^(-3)= 1/27
1/9/1/27-V18/V2= 1/9*27-V9= 27/9-3= 3-3= 0